Update paper

latex/problems/problem-1.tex

@@ -12,5 +12,5 @@ Scaling will result in a dimensionless variable $\hat{x} = \frac{1}{L}$.
 \end{align*}
 Now we insert the expression into the original equation
 \begin{align*}
-    \frac{d u(\hat{x})}{d\hat{x}^{2}} &= - \frac{F L^{2}}{\gamma} u(\hat{x}) \\
-\end{align*}
+    \frac{d u(\hat{x})}{d\hat{x}^{2}} &= - \frac{F L^{2}}{\gamma} u(\hat{x}). \\
+\end{align*}