Remove loose subsection

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2023-09-10 12:50:18 +02:00
parent 5cc45d0d02
commit b4325ec185

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@@ -53,6 +53,3 @@ For every iteration of i in forward sweep we have 2 division, and 2 additions, r
For backward sweep we have 1 division, and for every iteration of i we have 1 addition, and 1 division, resulting in $2(n-1)+1$ FLOPs. For backward sweep we have 1 division, and for every iteration of i we have 1 addition, and 1 division, resulting in $2(n-1)+1$ FLOPs.
Total FLOPs for the special algorithm is $6(n-1)+1$. Total FLOPs for the special algorithm is $6(n-1)+1$.
\subsection*{)}
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